Euler Problem 1

Problem:

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

Solution:

function euler1 (range)
 local result = 0
 
 for i=3,range do
  if (i % 3) == 0 or (i % 5) == 0 then
   result = result + i
  end
 end

 return result
end

print(euler1(999))

There's really nothing clever here, I just used the most straightforward way of accumulating the results imperatively. Mostly boring stuff, but now we are underway!